The full load current calculator calculates the full load current for 1-phase AC, 3-phase AC and DC loads in kW, kVA or hp. Includes step-by-step equations.

Voltage (V)

Load rating (A, hp, kW or kVA)
pf

• Voltage (V):
• Specify the phase-to-phase VLL voltage for a 3-phase AC supply in volts.
• Specify the the phase-to-neutral VLN voltage for a 1-phase AC or DC supply.
• Select the phase arrangement: 1 Phase AC,  3 phase AC, or DC.
• Load (S): Specify the the load in kW, kVA, A, or hp. And specify the load power factor (pf) (cosΦ) when the load is specified in kW or hp.

Full load current calculation for a 3-phase AC supply:

The full load current for a 3-phase load in kW is calculated as:

$$I=\displaystyle\frac{1000 \cdot S_{kW}} {\sqrt{3} \cdot V_{LL} \cdot \cos{\phi} }$$

Where:

• SkW: Is the rated power in kilowatt (kW)
• VLL: Is the line-to-line (phase-to-phase) voltage in volts.
• cosΦ: Is the load power factor.

The full load current for a 3-phase load in kVA is calculated as:

$$I=\displaystyle\frac{1000 \cdot S_{kVA}} {\sqrt{3} \cdot V_{LL} }$$

The full load current for a 3-phase load in hp is calculated as:

$$I=\displaystyle\frac{745.7 \cdot S_{hp}} {\sqrt{3} \cdot V_{LL} \cdot \cos{\phi} }$$

Full load current calculation for a 1-phase AC supply:

The full load current for a 1-phase load in kW is calculated as:

$$I=\displaystyle\frac{1000 \cdot S_{kW}} {V_{LN} \cdot \cos{\phi} }$$

The full load current for a 1-phase load in kVA is calculated as:

$$I=\displaystyle\frac{1000 \cdot S_{kVA}} {V_{LN} }$$

The full load current for a 1-phase load in hp is calculated as:

$$I=\displaystyle\frac{745.7 \cdot S_{hp}} {V_{LN} \cdot \cos{\phi} }$$

Full load current calculation for a DC supply:

The full load current for a DC load in kW is calculated as:

$$I=\displaystyle\frac{1000 \cdot S_{kW}} {V_{LN} }$$

The full load current for a DC load in kVA is calculated as:

$$I=\displaystyle\frac{1000 \cdot S_{kVA}} {V_{LN} }$$

The full load current for a DC load in hp is calculated as:

$$I=\displaystyle\frac{745.7 \cdot S_{hp}} {V_{LN} }$$